- anonymous

6x+3=y, How would i solve for "Y"

- jamiebookeater

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- anonymous

it is solved for y already

- anonymous

Is that the exact question you are looking at?

- anonymous

Then how would i graph it?

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## More answers

- anonymous

3 is the y-intercept, so (0,3) is a point on the graph. You just need to find one more point on the graph, plot it, and draw a line between the two points

- anonymous

How would i do that?

- anonymous

so if x = 1, then y = 6(1)+3 = 9, meaning (1, 9) is another point on the graph

- anonymous

wait lemme check it really qucik

- anonymous

Its wrong

- anonymous

How would you solve for X

- anonymous

what does your answer say?
that isn't wrong, but i'm not sure what your teacher wants

- anonymous

I described how to draw a picture (graph) of the line

- anonymous

Okay this is how the question is written: "Graph each linear equation?" Then its gives me the problem which is : y=6x+3

- anonymous

okay. you can use the method of plotting 2 points that I described to do that

- anonymous

or you can plot the y-intercept and use slope

- anonymous

Can you give me an example using this problem and using the y- intercepr and use slope method

- anonymous

The slope is 6 (the number in from of the x term). This means that for every 1 unit we move in the positive x direction, the line goes up 6 in the y direction

- anonymous

the y-intercept is (0, 3)
so using slope if we move to x = 1, we need to add 6 to y. So another point is
(1, 9)

- anonymous

Then another would be (2, 15), etc..

- anonymous

Wait lemme check again

- anonymous

you just need to plot 2 points that are on the line to draw the line

- anonymous

But in the back of my book the graph doesnt go that high, I only goes upto 5 and thats it.

- anonymous

oh, ok

- anonymous

I am still confused.

- anonymous

The previouis problem was x-2y=6 and this one was the one after

- anonymous

You can still plot two points and draw a line through them, the book just didn't use nice whole numbers to graph its line

- anonymous

you could let y = 0 and find the x-intercept too

- anonymous

0 =6x+3
x = -1/2
so (-1/2, 0) is another point on the graph

- anonymous

you got Y already.

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