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it is solved for y already
Is that the exact question you are looking at?
Then how would i graph it?
3 is the y-intercept, so (0,3) is a point on the graph. You just need to find one more point on the graph, plot it, and draw a line between the two points
How would i do that?
so if x = 1, then y = 6(1)+3 = 9, meaning (1, 9) is another point on the graph
wait lemme check it really qucik
How would you solve for X
what does your answer say? that isn't wrong, but i'm not sure what your teacher wants
I described how to draw a picture (graph) of the line
Okay this is how the question is written: "Graph each linear equation?" Then its gives me the problem which is : y=6x+3
okay. you can use the method of plotting 2 points that I described to do that
or you can plot the y-intercept and use slope
Can you give me an example using this problem and using the y- intercepr and use slope method
The slope is 6 (the number in from of the x term). This means that for every 1 unit we move in the positive x direction, the line goes up 6 in the y direction
the y-intercept is (0, 3) so using slope if we move to x = 1, we need to add 6 to y. So another point is (1, 9)
Then another would be (2, 15), etc..
Wait lemme check again
you just need to plot 2 points that are on the line to draw the line
But in the back of my book the graph doesnt go that high, I only goes upto 5 and thats it.
I am still confused.
The previouis problem was x-2y=6 and this one was the one after
You can still plot two points and draw a line through them, the book just didn't use nice whole numbers to graph its line
you could let y = 0 and find the x-intercept too
0 =6x+3 x = -1/2 so (-1/2, 0) is another point on the graph
you got Y already.