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anonymous

  • 5 years ago

{n^2/2^n} does the sequence converge or diverge if it converges how do u find the limit?

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  1. anonymous
    • 5 years ago
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    http://www.youtube.com/watch?v=wV1FrqwZyKw&feature=feedlik

  2. anonymous
    • 5 years ago
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    Use the ratio test: \[\lim_{n \rightarrow \infty} \frac{\frac{(n+1)^2}{2^{n+1}}}{\frac{2^n}{n^2}}\]

  3. anonymous
    • 5 years ago
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    = \[\lim_{n \rightarrow \infty} \frac{(n+1)^2}{2^{n+1}} \frac{2^n}{n^2} = \lim_{n \rightarrow \infty} \frac{1}{2}\frac{(n+1)^2}{n^2}\]

  4. anonymous
    • 5 years ago
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    or you could watch the vid: http://www.youtube.com/watch?v=wV1FrqwZyKw&feature=feedlik

  5. anonymous
    • 5 years ago
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    which equals (1/2). So the ratio test says that if the ratio yeilds something less than 1, the series converges

  6. anonymous
    • 5 years ago
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    ohh ok i was trying to aproach this using the nth term test

  7. anonymous
    • 5 years ago
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    http://www.youtube.com/watch?v=wV1FrqwZyKw&feature=feedlik

  8. anonymous
    • 5 years ago
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    if you try using the n-th term test, you'll get 0, which is inconclusive.

  9. anonymous
    • 5 years ago
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    http://www.youtube.com/watch?v=wV1FrqwZyKw&feature=feedlik

  10. anonymous
    • 5 years ago
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    http://www.youtube.com/watch?v=wV1FrqwZyKw&feature=feedlik

  11. anonymous
    • 5 years ago
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    http://www.youtube.com/watch?v=wV1FrqwZyKw&feature=feedlik

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