anonymous
  • anonymous
How do you solve for higher order derivatives for example 90th derivative of cos(2x)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
http://www.youtube.com/watch?v=wV1FrqwZyKw&feature=feedlik
anonymous
  • anonymous
Write out a couple of the first few derivatives: f(x) = cos(2x) f'(x) = -2sin(2x) f''(x) = -4cos(2x) f'''(x) = 8sin(2x) f(4)(x) = 16cos(2x) the key is to notice the pattern. Every 4 derivatives taken the expression reverts back to cosine. With every derivative the coefficient doubles. So the 88th derivative is a positive cosine, then the 90th must be a negative cosine, with the coefficient equal to 2^90 f(90)(x) = -(2^90)cos(2x)
anonymous
  • anonymous
thanks so much

Looking for something else?

Not the answer you are looking for? Search for more explanations.