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find derivate of - 3/ x^3

Mathematics
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is this +9/ X^4
quotient rule= (x^3)(-3)'-(x^3)'(-3) all over x^6 so this = (x^3)(0)-(3x^2)(-3) all over x^6
the problem i get from my book is find derivate f(x)=3X^3 - (8X^3/4 DIVIDED 3) - (3 / x^3

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Other answers:

SO MY ANSWER IS 9X^2 - 2X^-1/4 + 9X^-4 IS THIS CORRECT
-9x^2
but you just pulled a part from the question, thats why i solved only for that derivative because its still -9x^2/x^6
or 9/x^4 so yea you are right 9x^-4
but that should still be -9x^-4
OK SO THE 3RD TERM IS NEGATIVE THANK YOU
is the problem -(3/x^3) or -3/x^3
itll be positive if it becomes -(-9x^-4)=9x^-4 if there isnt a negative, it will stay -9x^-4
-(3/x^3) THE PROBLEM
then its negative
because its 9x^2/x^6=9/x^4=9x^-4 then -(9x^-4)=-9x^-4
OK THANKS I JUST THOUGHT THAT BECAUSE X^3 DE DENOMINATOR IF I BRING IT UP IT WILL BE -(3X^-3) SO THEN IT WILL BE POSITIVE
its fine, you just have to do the quotient rule, and then at the end associate the negative with the derivative you found for the section

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