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anonymous

  • 5 years ago

find derivate of - 3/ x^3

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  1. anonymous
    • 5 years ago
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    is this +9/ X^4

  2. anonymous
    • 5 years ago
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    quotient rule= (x^3)(-3)'-(x^3)'(-3) all over x^6 so this = (x^3)(0)-(3x^2)(-3) all over x^6

  3. anonymous
    • 5 years ago
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    the problem i get from my book is find derivate f(x)=3X^3 - (8X^3/4 DIVIDED 3) - (3 / x^3

  4. anonymous
    • 5 years ago
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    SO MY ANSWER IS 9X^2 - 2X^-1/4 + 9X^-4 IS THIS CORRECT

  5. anonymous
    • 5 years ago
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    -9x^2

  6. anonymous
    • 5 years ago
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    but you just pulled a part from the question, thats why i solved only for that derivative because its still -9x^2/x^6

  7. anonymous
    • 5 years ago
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    or 9/x^4 so yea you are right 9x^-4

  8. anonymous
    • 5 years ago
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    but that should still be -9x^-4

  9. anonymous
    • 5 years ago
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    OK SO THE 3RD TERM IS NEGATIVE THANK YOU

  10. anonymous
    • 5 years ago
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    is the problem -(3/x^3) or -3/x^3

  11. anonymous
    • 5 years ago
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    itll be positive if it becomes -(-9x^-4)=9x^-4 if there isnt a negative, it will stay -9x^-4

  12. anonymous
    • 5 years ago
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    -(3/x^3) THE PROBLEM

  13. anonymous
    • 5 years ago
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    then its negative

  14. anonymous
    • 5 years ago
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    because its 9x^2/x^6=9/x^4=9x^-4 then -(9x^-4)=-9x^-4

  15. anonymous
    • 5 years ago
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    OK THANKS I JUST THOUGHT THAT BECAUSE X^3 DE DENOMINATOR IF I BRING IT UP IT WILL BE -(3X^-3) SO THEN IT WILL BE POSITIVE

  16. anonymous
    • 5 years ago
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    its fine, you just have to do the quotient rule, and then at the end associate the negative with the derivative you found for the section

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