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anonymous

  • 5 years ago

what is dx/dy of 2x-5x^3y^2+4y=4?

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  1. anonymous
    • 5 years ago
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    is the middle term 5x^3 and y^2

  2. anonymous
    • 5 years ago
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    yes

  3. anonymous
    • 5 years ago
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    so then you have to do the product rule of that middle section

  4. anonymous
    • 5 years ago
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    so fg'+f'g

  5. anonymous
    • 5 years ago
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    2x-[5x^3*dy/dx(2y)+(15x^2)(y^2)]+dy/dx(4y)=4

  6. anonymous
    • 5 years ago
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    then you have to isolate dy/dx

  7. anonymous
    • 5 years ago
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    I was screwing up the 2nd part of the problem. I wasn't doing the y^2

  8. anonymous
    • 5 years ago
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    are you good now?

  9. anonymous
    • 5 years ago
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    I think so. Thanks a bunch. I should have done this 25 years ago when I knew this stuff.

  10. anonymous
    • 5 years ago
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    yea just isolate the dy/dx, implicit differentiation isnt too bad. You should be fine now

  11. anonymous
    • 5 years ago
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    Thank you

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