anonymous
  • anonymous
FIND DERIVATE (3T)(SINT / T) - ( T^2 / 3)
Mathematics
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anonymous
  • anonymous
FIND DERIVATE (3T)(SINT / T) - ( T^2 / 3)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
wow you have product rule, and quotient. Ive never seen that before but its pretty simple
anonymous
  • anonymous
\[(3T)(SINT / T) - ( T^2 / 3) \] it is that your equation?
anonymous
  • anonymous
YES I KNOW IT SEEMS EASY BUT THAT COULD NOT BE AN EASY ANSWER MY PROFFESOR LIKES TO GIVE TRICKY QUESTIONS

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anonymous
  • anonymous
3cost - 2/3(t)
anonymous
  • anonymous
(3T)[(T)(cos(t)-(1)(sin(t)]/t^2]+(3)(sint/t))-(3)(2t)-(t^2)(0)/9
anonymous
  • anonymous
its such a crazy combination but that should be right
anonymous
  • anonymous
I GET 3COST BUT NOT -2/3T
anonymous
  • anonymous
isnt sin t/t=1?
anonymous
  • anonymous
the derivative of 3sint = 3cost derivative of (-t^2/3) = -2/3 (t) together 3cost-(2/3)t
anonymous
  • anonymous
(3T)(1)-(T^/3) = 3-[3(1)/9]=3-1/3=3/3-1/3=2/3
anonymous
  • anonymous
the answer is just 2/3 rewrite it
anonymous
  • anonymous
SINT/T is an identity which can be rewritten as =1
anonymous
  • anonymous
we are talking about the derivative... not limits
anonymous
  • anonymous
for limits we know that sint/t = 1 but the question said FIND THE DERIVATIVE
anonymous
  • anonymous
yea then you are right 3cosT-2/3T
anonymous
  • anonymous
OK I THINK THIS IS WERE I WAS CONFUSED IS NOT -T^ RAISED TO THE 2/3 I KNOW U BRING THE 2/3 BEFORE THE T
anonymous
  • anonymous
IS T^2 THIS TERM DIVIDED BY 3
anonymous
  • anonymous
shouldnt it still be raised to the -1/3
anonymous
  • anonymous
TO FIND DERIVATE SO DONT WE HAVE TO MULTIPLY KINDA OF 3T THE OUTSIDE (SINT/T) MINUS (T^2 DIVIDED BY 3)

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