anonymous
  • anonymous
solve: y^2/3=64
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
y=64^(3/2)=8^3
anonymous
  • anonymous
y= 16?
anonymous
  • anonymous
but the choices are +512 or +16 or 16 or 512 the last two are listed without positvie sign but dont have a neg either

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anonymous
  • anonymous
Well, -8^3 works as well. 8^3 is 512, by the way.
anonymous
  • anonymous
Is your question y^2*1/3=64 or y^(2/3)=64?
anonymous
  • anonymous
so would i chose +512 or just 512
anonymous
  • anonymous
I don't think there's a difference unfortunately.
anonymous
  • anonymous
its y^(2/3)=62
anonymous
  • anonymous
y = \[y=\sqrt([3]{63}) then ^2 \it\], i agree no plus or minus,
anonymous
  • anonymous
Well, the answer is 512 or -512. Either one works.
anonymous
  • anonymous
i mean 64
anonymous
  • anonymous
but mirwiz has right answer and order of operation
anonymous
  • anonymous
so i figure im ganna go with just 512
anonymous
  • anonymous
Yeah... I guess so. That's stupid. 512 is the same as +512.
anonymous
  • anonymous
i know idk y its a choice
anonymous
  • anonymous
i also had another similar question z^(3/2) = 64
anonymous
  • anonymous
It's the same thing as (z^(1/2))^3=64. z^(1/2)=64^(1/3)=4 z=16. -16 is not a solution here because you can sqrt a negative number.
anonymous
  • anonymous
wut bout (w+1)^(3/2)=64
anonymous
  • anonymous
The same thing, except you subtract 1.
anonymous
  • anonymous
from 64?

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