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anonymous

  • 5 years ago

solve: y^2/3=64

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  1. anonymous
    • 5 years ago
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    y=64^(3/2)=8^3

  2. anonymous
    • 5 years ago
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    y= 16?

  3. anonymous
    • 5 years ago
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    but the choices are +512 or +16 or 16 or 512 the last two are listed without positvie sign but dont have a neg either

  4. anonymous
    • 5 years ago
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    Well, -8^3 works as well. 8^3 is 512, by the way.

  5. anonymous
    • 5 years ago
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    Is your question y^2*1/3=64 or y^(2/3)=64?

  6. anonymous
    • 5 years ago
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    so would i chose +512 or just 512

  7. anonymous
    • 5 years ago
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    I don't think there's a difference unfortunately.

  8. anonymous
    • 5 years ago
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    its y^(2/3)=62

  9. anonymous
    • 5 years ago
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    y = \[y=\sqrt([3]{63}) then ^2 \it\], i agree no plus or minus,

  10. anonymous
    • 5 years ago
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    Well, the answer is 512 or -512. Either one works.

  11. anonymous
    • 5 years ago
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    i mean 64

  12. anonymous
    • 5 years ago
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    but mirwiz has right answer and order of operation

  13. anonymous
    • 5 years ago
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    so i figure im ganna go with just 512

  14. anonymous
    • 5 years ago
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    Yeah... I guess so. That's stupid. 512 is the same as +512.

  15. anonymous
    • 5 years ago
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    i know idk y its a choice

  16. anonymous
    • 5 years ago
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    i also had another similar question z^(3/2) = 64

  17. anonymous
    • 5 years ago
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    It's the same thing as (z^(1/2))^3=64. z^(1/2)=64^(1/3)=4 z=16. -16 is not a solution here because you can sqrt a negative number.

  18. anonymous
    • 5 years ago
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    wut bout (w+1)^(3/2)=64

  19. anonymous
    • 5 years ago
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    The same thing, except you subtract 1.

  20. anonymous
    • 5 years ago
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    from 64?

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