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did u mean:
\[\sqrt{2x+16}-\sqrt{x} = 4\]

yes

first square both sides.
so it should next look like this:
2x+16-x=4^2

u can't do that

theyr not under the same square root

no? is it becuase they're two different terms?

oh, right! duhh. basic rules!

okay try other method...

what method?

id multiply both sides by sqrt(2x+16)+sqrt(x)

to get:
2x+16-x = 4[sqrt(2x+16) + sqrt(x)]

x + 16 = 4(sqrt(2x+16)+sqrtx)

ok thanks

i honestly dunno what do now.. lol havent done this in a while..

same here, thats why i messed up. sorry! lemme remember and ill help you in a sec!