anonymous
  • anonymous
squarre root of 2x+16- square root of x =4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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bahrom7893
  • bahrom7893
did u mean: \[\sqrt{2x+16}-\sqrt{x} = 4\]
anonymous
  • anonymous
yes
anonymous
  • anonymous
first square both sides. so it should next look like this: 2x+16-x=4^2

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bahrom7893
  • bahrom7893
u can't do that
bahrom7893
  • bahrom7893
theyr not under the same square root
anonymous
  • anonymous
no? is it becuase they're two different terms?
anonymous
  • anonymous
oh, right! duhh. basic rules!
bahrom7893
  • bahrom7893
okay try other method...
anonymous
  • anonymous
what method?
bahrom7893
  • bahrom7893
id multiply both sides by sqrt(2x+16)+sqrt(x)
bahrom7893
  • bahrom7893
to get: 2x+16-x = 4[sqrt(2x+16) + sqrt(x)]
bahrom7893
  • bahrom7893
x + 16 = 4(sqrt(2x+16)+sqrtx)
anonymous
  • anonymous
ok thanks
bahrom7893
  • bahrom7893
i honestly dunno what do now.. lol havent done this in a while..
anonymous
  • anonymous
same here, thats why i messed up. sorry! lemme remember and ill help you in a sec!

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