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squarre root of 2x+16- square root of x =4

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did u mean: \[\sqrt{2x+16}-\sqrt{x} = 4\]
first square both sides. so it should next look like this: 2x+16-x=4^2

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Other answers:

u can't do that
theyr not under the same square root
no? is it becuase they're two different terms?
oh, right! duhh. basic rules!
okay try other method...
what method?
id multiply both sides by sqrt(2x+16)+sqrt(x)
to get: 2x+16-x = 4[sqrt(2x+16) + sqrt(x)]
x + 16 = 4(sqrt(2x+16)+sqrtx)
ok thanks
i honestly dunno what do now.. lol havent done this in a while..
same here, thats why i messed up. sorry! lemme remember and ill help you in a sec!

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