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anonymous

  • 5 years ago

help with porabolas

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  1. anonymous
    • 5 years ago
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    Parabolas? Just ask the question.

  2. anonymous
    • 5 years ago
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    same here.

  3. anonymous
    • 5 years ago
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    how to find focus,directix and intercepts question: -1/3(y-6)=(x-5)^2

  4. anonymous
    • 5 years ago
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    Sorry, I don't remember how to do this, but try http://www.purplemath.com/modules/parabola.htm I used that when I took Algebra 2.

  5. Chris
    • 5 years ago
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    for the intercepts, you want to know when it crosses either axis - so x = 0 or y = 0, place those into the equation

  6. Chris
    • 5 years ago
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    for the focus, use this guide: http://www.mathwords.com/f/focus_parabola.htm

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