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anonymous
 5 years ago
Hi does anyone know how to solve this problem???
Let A and B be square matrices of order 2 such that
A1 = 1 2 and (AB)−1= −2 3
1 3 3 −4
find B..
anonymous
 5 years ago
Hi does anyone know how to solve this problem??? Let A and B be square matrices of order 2 such that A1 = 1 2 and (AB)−1= −2 3 1 3 3 −4 find B..

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here's a hint. A = [2 3;0 4] AB = [1 4; 4 3]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(AB)^1 = (B)^1 * (A)^1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you say A1 you mean A^1 (The inverse)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i mean the inverse @ daramda

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Corec pointed you in the right direction, use that equation to set up another system of equations and solve for the inverse of matrix B. Then find the inverse of the inverse of matrix B which is the solution.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0As long as I understand the question correctly (both A and B are square matrices): B=[(10/29), (7/29); (25/29), (3/29)}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.010 7 5 3 THAT ARE THE VALUE OF B .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you all for your help! havent gotten around to doing it yet but will let you know if I get it. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0[10, 7; 5,3] is correct. I ran the math again on my solution, and it assigns [2, 3; 7, 4] to (AB)^1, so it looks like I failed at simple arithmetic. Nice catch corec ; )
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