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anonymous

  • 5 years ago

can someone please help me with these equations of definite integrals in integration? ∫ x/sqrt 2x - 1 dx from 5 to 1 ∫ e^3/x//x^2 dx from 3 to 1 -- this is e to the power 3 over x, all over x squared. I hope that makes sense.

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  1. anonymous
    • 5 years ago
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    \[\int\limits_{3}^{1} (e^3/x)/x^2 \] this what you mean?

  2. anonymous
    • 5 years ago
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    kinda of... but its e to the power 3/x.

  3. anonymous
    • 5 years ago
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    ln(2)/4 - ln(18)/4 - 2/9

  4. anonymous
    • 5 years ago
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    \[\int\limits_{5}^{1}x/(2x-1)^2\] =\[\ln(2)/4 - \ln(18)/4 - 2/9 \]

  5. anonymous
    • 5 years ago
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    regarding e^(3/x)/x^2 the derivative of 3/x is is -3/x^2 so let use substitution u=3/x du= -3/x^2 now we can do integral e^(u)*du take out the -1/3 ofcouse. so you should have \[-1/3\int\limits_{?}^{?} e^udu \] that should push you thou now sure about my answer:D but hope i helped

  6. anonymous
    • 5 years ago
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    thank you... any help is appreciated!! :)

  7. anonymous
    • 5 years ago
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    lol

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