anonymous
  • anonymous
How can I solve this indefinite integral without having arcsin in the result? \int \sqrt{1-x^2} dx Thanks!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
The integral is this: \[\int\limits \sqrt{1-x^2} dx\]
anonymous
  • anonymous
i dont see how you got arcsin? /int for arsin is 1/(a^2 -x^2)^.5
anonymous
  • anonymous
\[1/\sqrt{(a^2 - x^2)}\]

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anonymous
  • anonymous
I solved it with this substitution x=sin(t) result: 1/2arcsin(x)+1/4sin(2arcsin(x))
anonymous
  • anonymous
I LOL YOU

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