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anonymous
 5 years ago
How can I solve this indefinite integral without having arcsin in the result?
\int \sqrt{1x^2} dx Thanks!
anonymous
 5 years ago
How can I solve this indefinite integral without having arcsin in the result? \int \sqrt{1x^2} dx Thanks!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The integral is this: \[\int\limits \sqrt{1x^2} dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont see how you got arcsin? /int for arsin is 1/(a^2 x^2)^.5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/\sqrt{(a^2  x^2)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I solved it with this substitution x=sin(t) result: 1/2arcsin(x)+1/4sin(2arcsin(x))
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