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anonymous

  • 5 years ago

Find the slope of the line containing the pair of points (8,-1) & (-8,-1).

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  1. anonymous
    • 5 years ago
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    You do rise over run, \[m=(y2-y1)\div(x2-x1)\] so m=(1-(-1))/(-8-8)..m=0/-16, the slope is zero, if you draw the graph you will see that it is a horizontal line

  2. anonymous
    • 5 years ago
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    *that's not right, i didnt see the -1

  3. anonymous
    • 5 years ago
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    scratch that, lol, the equation is right, m=0, I just put 1 as y2 instead of -1 in the slope equation

  4. anonymous
    • 5 years ago
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    Ok so what is the slope of the line?

  5. anonymous
    • 5 years ago
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    the slope (m)=0/16, which is a slope of 0....m=0

  6. anonymous
    • 5 years ago
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    when in doubt draw a quick graph

  7. anonymous
    • 5 years ago
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    Ok thank you. Sorry it took so long to reply. Was writing a narrative essay, fun fun. NOT.

  8. anonymous
    • 5 years ago
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    haha, np, essays are horrible, well good luck

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