anonymous
  • anonymous
I had to take measurements and they are as follows. 45 degress at 32 meters and 7.5 meters from the distance of where I was standing to what i was measuring. How do I set up this equation using sine?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
I'm confused, you're saying that the length of your hypotenuse is 32?
anonymous
  • anonymous
That is what I am trying to figure out. These are measurements I had to take in a field method class.
anonymous
  • anonymous
With those numbers I am trying to acquire a height of the object being mesured

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anonymous
  • anonymous
Until I know whether 32 is either your hypotenuse or your y value, I can't help you. ... Okay then, so 32 is your hypotenuse.
anonymous
  • anonymous
Has your teacher taught you about SOH CAH TOA yet?
anonymous
  • anonymous
I am just now in trig and I was taught that phrase on Monday, briefly
anonymous
  • anonymous
Basically SOH CAH TOA tells you which trig function to use when you are given an angle and two sides. O = Opposite A = Adjacent H = Hypotenuse S = Sine C = Cosine T = Tangent When you're given the Opposite side (in relation to the angle) and the hypotenuse, you use Sine (SOH) The same pattern follows for the rest of SOH CAH TOA
anonymous
  • anonymous
So in your problem, which sides are you given?
anonymous
  • anonymous
Ok thanks. That helps. 7.5 would be the length of the base of the triangle
anonymous
  • anonymous
I have the answer if you want to compare what you got to what I got.

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