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anonymous

  • 5 years ago

I had to take measurements and they are as follows. 45 degress at 32 meters and 7.5 meters from the distance of where I was standing to what i was measuring. How do I set up this equation using sine?

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  1. anonymous
    • 5 years ago
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    I'm confused, you're saying that the length of your hypotenuse is 32?

  2. anonymous
    • 5 years ago
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    That is what I am trying to figure out. These are measurements I had to take in a field method class.

  3. anonymous
    • 5 years ago
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    With those numbers I am trying to acquire a height of the object being mesured

  4. anonymous
    • 5 years ago
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    Until I know whether 32 is either your hypotenuse or your y value, I can't help you. ... Okay then, so 32 is your hypotenuse.

  5. anonymous
    • 5 years ago
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    Has your teacher taught you about SOH CAH TOA yet?

  6. anonymous
    • 5 years ago
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    I am just now in trig and I was taught that phrase on Monday, briefly

  7. anonymous
    • 5 years ago
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    Basically SOH CAH TOA tells you which trig function to use when you are given an angle and two sides. O = Opposite A = Adjacent H = Hypotenuse S = Sine C = Cosine T = Tangent When you're given the Opposite side (in relation to the angle) and the hypotenuse, you use Sine (SOH) The same pattern follows for the rest of SOH CAH TOA

  8. anonymous
    • 5 years ago
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    So in your problem, which sides are you given?

  9. anonymous
    • 5 years ago
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    Ok thanks. That helps. 7.5 would be the length of the base of the triangle

  10. anonymous
    • 5 years ago
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    I have the answer if you want to compare what you got to what I got.

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