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anonymous
 5 years ago
What is the maximum height, And when does it occur? h(t)=16t^(2)+80t+3. Please help.
anonymous
 5 years ago
What is the maximum height, And when does it occur? h(t)=16t^(2)+80t+3. Please help.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the maximum height of this parabola is basically the vertex. so if you find the vertex, then there's your maximum height.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Have you learned about derivatives yet?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find the derivative of your function, and set it equal to zero, and solve for t. That will tell you when it occurred.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So 0 = Derivative of function.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you stay on here, I can verify your work as you work through it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it f(0)=83 or (0,80)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Still solving that, but that doesn't seem correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you sure it's +80t and not 80t? From what I know, negative time doesn't exist.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, the other way around.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the problem says h(t)=16t^(2)+80t+3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Aaaah! I see. When you posted your problem, the negative sign was cut off so all I saw was 16t^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright, I solved it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Where do you need help?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you're just completely lost I can walk you through it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that would help ALOT.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sounds good! Okay, so your function is f(t) = 16t^2 + 80t + 3 The derivative of that function is (df/dt) = 32t + 80 Does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The function reaches its maximum height when the derivative, or the slope, is equal to zero. It's kind of like when you throw a ball in the air. The moment the ball reaches the top of its arc, that's when the slope is zero. So what you do is set the derivative to zero ... 32t + 80 = (df/dt) 32t + 80 = 0 Given that easy formula, solve for t and let me know what you get.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's just algebra at this point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah! Awesome! Now, you plug that into h(t) and the number you get is your height.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And then you're done! :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I HAve Another One or You.
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