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anonymous

  • 5 years ago

What is the maximum height, And when does it occur? h(t)=-16t^(2)+80t+3. Please help.

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  1. anonymous
    • 5 years ago
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    the maximum height of this parabola is basically the vertex. so if you find the vertex, then there's your maximum height.

  2. anonymous
    • 5 years ago
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    Have you learned about derivatives yet?

  3. anonymous
    • 5 years ago
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    yes,

  4. anonymous
    • 5 years ago
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    Find the derivative of your function, and set it equal to zero, and solve for t. That will tell you when it occurred.

  5. anonymous
    • 5 years ago
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    So 0 = Derivative of function.

  6. anonymous
    • 5 years ago
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    okay thx guys :)

  7. anonymous
    • 5 years ago
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    If you stay on here, I can verify your work as you work through it.

  8. anonymous
    • 5 years ago
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    is it f(0)=83 or (0,80)

  9. anonymous
    • 5 years ago
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    Still solving that, but that doesn't seem correct.

  10. anonymous
    • 5 years ago
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    ill keep trying.

  11. anonymous
    • 5 years ago
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    Are you sure it's +80t and not -80t? From what I know, negative time doesn't exist.

  12. anonymous
    • 5 years ago
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    Sorry, the other way around.

  13. anonymous
    • 5 years ago
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    the problem says h(t)=-16t^(2)+80t+3

  14. anonymous
    • 5 years ago
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    Aaaah! I see. When you posted your problem, the negative sign was cut off so all I saw was 16t^2

  15. anonymous
    • 5 years ago
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    Alright, I solved it.

  16. anonymous
    • 5 years ago
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    Where do you need help?

  17. anonymous
    • 5 years ago
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    If you're just completely lost I can walk you through it.

  18. anonymous
    • 5 years ago
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    that would help ALOT.

  19. anonymous
    • 5 years ago
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    Sounds good! Okay, so your function is f(t) = -16t^2 + 80t + 3 The derivative of that function is (df/dt) = -32t + 80 Does that make sense?

  20. anonymous
    • 5 years ago
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    yess.

  21. anonymous
    • 5 years ago
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    The function reaches its maximum height when the derivative, or the slope, is equal to zero. It's kind of like when you throw a ball in the air. The moment the ball reaches the top of its arc, that's when the slope is zero. So what you do is set the derivative to zero ... -32t + 80 = (df/dt) -32t + 80 = 0 Given that easy formula, solve for t and let me know what you get.

  22. anonymous
    • 5 years ago
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    It's just algebra at this point.

  23. anonymous
    • 5 years ago
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    does t= 5/2?

  24. anonymous
    • 5 years ago
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    Yeah! Awesome! Now, you plug that into h(t) and the number you get is your height.

  25. anonymous
    • 5 years ago
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    And then you're done! :D

  26. anonymous
    • 5 years ago
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    THANKS SO MUCH!

  27. anonymous
    • 5 years ago
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    No problem :)

  28. anonymous
    • 5 years ago
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    I HAve Another One or You.

  29. anonymous
    • 5 years ago
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    *for

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