What is the maximum height, And when does it occur? h(t)=-16t^(2)+80t+3. Please help.

- anonymous

What is the maximum height, And when does it occur? h(t)=-16t^(2)+80t+3. Please help.

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

the maximum height of this parabola is basically the vertex. so if you find the vertex, then there's your maximum height.

- anonymous

Have you learned about derivatives yet?

- anonymous

yes,

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Find the derivative of your function, and set it equal to zero, and solve for t. That will tell you when it occurred.

- anonymous

So 0 = Derivative of function.

- anonymous

okay thx guys :)

- anonymous

If you stay on here, I can verify your work as you work through it.

- anonymous

is it f(0)=83 or (0,80)

- anonymous

Still solving that, but that doesn't seem correct.

- anonymous

ill keep trying.

- anonymous

Are you sure it's +80t and not -80t? From what I know, negative time doesn't exist.

- anonymous

Sorry, the other way around.

- anonymous

the problem says h(t)=-16t^(2)+80t+3

- anonymous

Aaaah! I see. When you posted your problem, the negative sign was cut off so all I saw was 16t^2

- anonymous

Alright, I solved it.

- anonymous

Where do you need help?

- anonymous

If you're just completely lost I can walk you through it.

- anonymous

that would help ALOT.

- anonymous

Sounds good!
Okay, so your function is f(t) = -16t^2 + 80t + 3
The derivative of that function is (df/dt) = -32t + 80
Does that make sense?

- anonymous

yess.

- anonymous

The function reaches its maximum height when the derivative, or the slope, is equal to zero.
It's kind of like when you throw a ball in the air. The moment the ball reaches the top of its arc, that's when the slope is zero.
So what you do is set the derivative to zero ...
-32t + 80 = (df/dt)
-32t + 80 = 0
Given that easy formula, solve for t and let me know what you get.

- anonymous

It's just algebra at this point.

- anonymous

does t= 5/2?

- anonymous

Yeah! Awesome!
Now, you plug that into h(t) and the number you get is your height.

- anonymous

And then you're done! :D

- anonymous

THANKS SO MUCH!

- anonymous

No problem :)

- anonymous

I HAve Another One or You.

- anonymous

*for

Looking for something else?

Not the answer you are looking for? Search for more explanations.