A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

A farmer is trying to build a chicken coop to hold all of his chickens. He has 460 meters of fence to use to build the coop and one side of the coop will be placed against the barn. Draw a picture to represent the situation. Then write a function representing the area of the chicken coop. What are the dimentions length and width of the coop with the larget area? What is the maximum area?

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Geez you're really testing me here. It's Calc 1 all over again.

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thats what math im in lol.

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I need to head to dinner since I have a paper due tomorrow, but I'll tell you what you need to do. You need to make two functions, one that represents area, one that represents perimeter. Your equation for perimeter should be equal to 460. I'll be back on in half an hour, hopefully once you get your area function and perimeter function, it shouldn't be too hard to solve for length and width. As a hint, Let x = l (length).

  4. radar
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Your perimeter may be more than 460 as the length of the barn comes into play it is part of the perimeter. I would let x be the length of the barn. Then the 460 meters of fence will make up the remaining three sides. One of the three sides will also be x (side opposite the barn. the other two sides will be (460-x)/2 each. The area will be A=x*(460-x)/2 or(460x-x^2)/2 Now differentiate that and set to 0 and solve.

  5. radar
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    A=-1/2 x^2+230 differntiating : -x+230 . for max/min let equal 0. 0=-x+230, solve for x, x=230 so the barn is 230meters, the opposite side is 230 meters, the other 2 sides are (460-230)/2=115 meters each.

  6. radar
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Messed up equation for area omitted the x at the end of 230 in equation for Area. Do you follow?

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.