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find the slope of the secant line that passes through (.1, .01) and (.5, .25)

sorry, my browser crashed

is the interval [0, 1/2] or [0.1, 1/2]?

well, I'll assume [0, 1/2] then. Let's say f(x) = x^2

Then the slope of the line between (0, f(0) and (.5, f(.5)) is
(.25-0)/(.5-0) = 0.5

sorry I crashed too haha

so f'(x) = 2x = 0.5
x = 0.25

so is d 0.25?

yes

well, no actually

d is 0.5

oh k, that makes more sense

because f'(0.25) = 0.5
so c = 0.25
d = 0.5

thanks a lot

no problem