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anonymous

  • 5 years ago

factor this 15=8x^2-14x

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  1. anonymous
    • 5 years ago
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    ok, so first you must subtract 15 on both sides, to get the three terms: 15=8x^2-14x 0=8x^2-14x-15

  2. anonymous
    • 5 years ago
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    \[0=8x^2-14x-15 \]

  3. anonymous
    • 5 years ago
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    ill brb

  4. anonymous
    • 5 years ago
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    what e thos pic mathfreak

  5. anonymous
    • 5 years ago
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    ok, sorry im back

  6. anonymous
    • 5 years ago
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    so now we have to sind a value that when multiplied, it equals -15.

  7. anonymous
    • 5 years ago
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    the only two numbers that could equal -15, would be -3*5, or -5*3

  8. anonymous
    • 5 years ago
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    lets first try 3*-5 (4x+3)(2x-5) next we multiply it out and see if we get back to our original problem. :15=8x^2-14x

  9. anonymous
    • 5 years ago
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    (4x+3)(2x-5) 8x^2-20x+6x-15 8x^2-14x-15. we know this is right, because we got back to:8x^2-14x-15

  10. anonymous
    • 5 years ago
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    so (4x+3)(2x-5) is the right answer

  11. anonymous
    • 5 years ago
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    when we multiply that out, we get : x^2+2x-3. which means this is right. remember how we divided -6x^2? well this is when we put it back. so the final factored answer is: -6x^2(x^2+2x-3)

  12. anonymous
    • 5 years ago
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    sorry, wrong place

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