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anonymous

  • 5 years ago

how do you factor this: -6x^4-12x^3+18x?

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  1. anonymous
    • 5 years ago
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    ok, so what's something they all have in common?

  2. anonymous
    • 5 years ago
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    6

  3. anonymous
    • 5 years ago
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    great, and...

  4. anonymous
    • 5 years ago
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    and X?

  5. anonymous
    • 5 years ago
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    yep, so you could all divide them by 6x.-6x^2 would be better, to get rid of the negatives. just an idea. so you would then have: -6x^2(x^2+2x-18)

  6. anonymous
    • 5 years ago
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    i decided to divide it by -6^2, because we want our first value to be x^2, not x^3. we must also remember that the -6x^2 didn't just poof away. so we need to keep that. next we're going to factor for x^2+2x-18.

  7. anonymous
    • 5 years ago
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    ok

  8. anonymous
    • 5 years ago
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    do you think you can handle it from there, or do you want me to keep on going?

  9. anonymous
    • 5 years ago
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    so when we factor x^2 + 2x - 18 the -6x^2 stays to the side?

  10. anonymous
    • 5 years ago
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    do u mind helpin me with the next step?

  11. anonymous
    • 5 years ago
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    so far i have (for factoring x^2 +2x-18) x(x )(x )....do u have to find 2 numbers that equal 18?

  12. anonymous
    • 5 years ago
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    okay, im back sorry

  13. anonymous
    • 5 years ago
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    yes and yes. you can just ignore the -6x^2 for now, and add it in the end. and you do need to find two numbers that equal -18, not just 18.

  14. anonymous
    • 5 years ago
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    so first start of by list multiples of -18

  15. anonymous
    • 5 years ago
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    ok cool... -6 x 3 = -18

  16. anonymous
    • 5 years ago
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    so now i have x (x - 6) (x + 3)

  17. anonymous
    • 5 years ago
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    ok, so now multiply it out and see if you get x^2 +2x-18

  18. anonymous
    • 5 years ago
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    wait! i just noticed a huge mistake!

  19. anonymous
    • 5 years ago
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    ok

  20. anonymous
    • 5 years ago
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    we forgot to divide 18 by -6. so you need to factor for x^2+2x-3

  21. anonymous
    • 5 years ago
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    i hope i didnt confuse you!

  22. anonymous
    • 5 years ago
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    so now find factors for -3. this should be easier

  23. anonymous
    • 5 years ago
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    we could use -1 and 3: (x-1)(x+3)

  24. anonymous
    • 5 years ago
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    sry my computer froze ...im lost now

  25. anonymous
    • 5 years ago
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    so i shouldnt of used -18?

  26. anonymous
    • 5 years ago
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    when we multiply that out, we get : x^2+2x-3. which means this is right. remember how we divided -6x^2? well this is when we put it back. so the final factored answer is: -6x^2(x^2+2x-3)

  27. anonymous
    • 5 years ago
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    but where did the (x^2+2x-3) come from?

  28. anonymous
    • 5 years ago
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    nevermind...I figured it out! lol ...i strolled back up in the convo

  29. anonymous
    • 5 years ago
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    thank u so much...i just have 1 more quick question if u dnt mind

  30. anonymous
    • 5 years ago
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    ok, remeber when we divided -6x^2? we forgot to divide that on -18x.

  31. anonymous
    • 5 years ago
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    ok, lol. sorry for confusing you! i confused myself too. my cp kept freezing

  32. anonymous
    • 5 years ago
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    my comp was freezing too!

  33. anonymous
    • 5 years ago
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    Um...I think you factored -6x^2 out of 18x.

  34. anonymous
    • 5 years ago
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    when factoring 27^3 - 48x ... being that there is no common numbers between the both of them...what would be the 1st step?

  35. anonymous
    • 5 years ago
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    27^3 or 27x^3

  36. anonymous
    • 5 years ago
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    im sry 27x^3

  37. anonymous
    • 5 years ago
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    well then they can both be divided by x

  38. anonymous
    • 5 years ago
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    ohh! wait a sec. what grade are you in?

  39. anonymous
    • 5 years ago
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    so then i would have x(x )(x )...and then do i find #'s for 48?

  40. anonymous
    • 5 years ago
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    im in 12th grade

  41. anonymous
    • 5 years ago
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    have you learned about completing the square?

  42. anonymous
    • 5 years ago
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    whoa! im teaching a 12 grader. sorry. im a freshie_

  43. anonymous
    • 5 years ago
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    it doesn't sound familiar ... im really bad in math, its like another language to me!

  44. anonymous
    • 5 years ago
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    lol well u did a good job helpin me on the 1st 1 =)

  45. anonymous
    • 5 years ago
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    no prob, glad to help anytime

  46. anonymous
    • 5 years ago
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    so the answer is : -6x^2(x^2+2x-3) for the first one

  47. anonymous
    • 5 years ago
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    yea i got that 1

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