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ok, so what's something they all have in common?

great, and...

and X?

ok

do you think you can handle it from there, or do you want me to keep on going?

so when we factor x^2 + 2x - 18 the -6x^2 stays to the side?

do u mind helpin me with the next step?

so far i have (for factoring x^2 +2x-18) x(x )(x )....do u have to find 2 numbers that equal 18?

okay, im back sorry

so first start of by list multiples of -18

ok cool... -6 x 3 = -18

so now i have x (x - 6) (x + 3)

ok, so now multiply it out and see if you get x^2 +2x-18

wait! i just noticed a huge mistake!

ok

we forgot to divide 18 by -6. so you need to factor for x^2+2x-3

i hope i didnt confuse you!

so now find factors for -3. this should be easier

we could use -1 and 3:
(x-1)(x+3)

sry my computer froze ...im lost now

so i shouldnt of used -18?

but where did the (x^2+2x-3) come from?

nevermind...I figured it out! lol ...i strolled back up in the convo

thank u so much...i just have 1 more quick question if u dnt mind

ok, remeber when we divided -6x^2? we forgot to divide that on -18x.

ok, lol. sorry for confusing you! i confused myself too. my cp kept freezing

my comp was freezing too!

Um...I think you factored -6x^2 out of 18x.

27^3 or 27x^3

im sry 27x^3

well then they can both be divided by x

ohh! wait a sec. what grade are you in?

so then i would have x(x )(x )...and then do i find #'s for 48?

im in 12th grade

have you learned about completing the square?

whoa! im teaching a 12 grader. sorry. im a freshie_

it doesn't sound familiar ... im really bad in math, its like another language to me!

lol well u did a good job helpin me on the 1st 1 =)

no prob, glad to help anytime

so the answer is :
-6x^2(x^2+2x-3)
for the first one

yea i got that 1