how do you factor 27x^3 - 48x when they have no common numbers?

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how do you factor 27x^3 - 48x when they have no common numbers?

Mathematics
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Yes they do...they both share 3x.
so 3x would go on the outside of the parenthesis? like this: 3x(x )(x ) right?
Sort of... it would be 3x(9x^2-16).

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Then use difference of two squares to factor the 9x^2-16 into (3x+4)(3x-4)
So your final answer is 3x(3x+4)(3x-4)
thank u so much!
You're welcome. But do you know the difference of two squares?
isn't when u draw a box and factor that way?
NO! What you do is square root the first and last terms (only works when you can do this evenly and when the terms are being subtracted)
Your two factors are those two square roots, except one is plus and one is minus.
oohhh yeaaa i remember that...i didn't know it was called difference of 2 squares
Like (x+4)(x-4)
Oh. That's because it's a difference (subtraction) of two square numbers.
ohh ok ... thanks for explainin that

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