write an equation of the line containing the given point & perpendicular to the given line. (0,6); 3x+7y=5

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write an equation of the line containing the given point & perpendicular to the given line. (0,6); 3x+7y=5

Mathematics
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okey dokey, rewrite the equation in y = mx+b form
7y=5-3x y = -3x/7 + 5/7
The slope is the coefficient of the x term, -3/7 The slope of the perpendicular line is the negative reciprocal. This means flip and negate the fraction. The slope of the perpendicular line is thus 7/3

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so the line will be: y = 7/3(x-0)+6 = 7x/3 + 6

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