Determine the equation of the line tangent to the graph of the following function at x = 0. g(x) = ex(−4 + 3x + 3x2)

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Determine the equation of the line tangent to the graph of the following function at x = 0. g(x) = ex(−4 + 3x + 3x2)

Mathematics
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the eqn is y+4-6x^2-3x
y+4-6x^2-3x = 0 ***
how did you figure that one man?

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first you the y-value when x=0(so y=-4) and then when you find the equation of the tangent at any piont (aka, the slope) you use the slope, and your x and y value and sub them into the y=mx+b eqn to get it or you can use slope=(-4-y)/(o-x)
only one problem. we're looking for the equation of a straight line. so it couldn't have any squared values in it
true, okay the answer is y=3x+4
that was considered the wrong answer when i submitted
what grade are you in?
im a senior in high school
okay, and what's the ex in front of the eqn?
g(x) = e^x(−4 + 3x + 3x^2)
e to the power of x?
yezzir
whoa thats wierd, i didnt even consider that
just get the derivative using product rule, then sub 0 in for x and find the slope at that point, and then use y=mx+b, no big.
a'ight could you check my answer for me after i work it?
k go, young grasshopper
is there answers in the back of your text book or something?

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