anonymous
  • anonymous
Determine the equation of the line tangent to the graph of the following function at x = 0. g(x) = e^x(−4 + 3x + 3x^2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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bahrom7893
  • bahrom7893
okay tangent line is the first derivative
bahrom7893
  • bahrom7893
g(x) = e^x(−4 + 3x + 3x^2) g'(x) = (3+6x) * e^x(−4 + 3x + 3x^2)
bahrom7893
  • bahrom7893
woops sorry the derivative was wrong..

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bahrom7893
  • bahrom7893
didn't see the x, btw is it (e^x)(−4 + 3x + 3x^2)?
bahrom7893
  • bahrom7893
i mean is e^x separate?
anonymous
  • anonymous
product rule?
bahrom7893
  • bahrom7893
well yeah, but he doesn't specify... People use the freakin parenthesis, we have to guess what the heck was the original problem... Is (−4 + 3x + 3x^2) in the power too?
bahrom7893
  • bahrom7893
i mean we are all busy students and u guys can't even make our lives easier?? Please, use a calculator notation, we will understand it, sorry if I sounded to harsh earlier, I was mad at someone else.. =)
anonymous
  • anonymous
I think the equation of the tangent line is Y=-x-4
anonymous
  • anonymous
first input the value of x as g(0) to fine the value of y. Then find the derivative using the product rule. factor out the e^x, and collect like terms. Then input the value of x into the derivative to find the slope. g'(x)=m. then use point slope formula.
anonymous
  • anonymous
dear hix212, thank you for the help it was -x-4

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