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anonymous

  • 5 years ago

what is the answer to this problem when you plug in infinity for t 1/5ln(5t+2)?

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  1. anonymous
    • 5 years ago
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    0

  2. anonymous
    • 5 years ago
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    why isnt it infinity

  3. anonymous
    • 5 years ago
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    because any number divided by something approaching infinity goes to 0

  4. anonymous
    • 5 years ago
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    i wrote my question wrong

  5. anonymous
    • 5 years ago
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    is ln(5t+2) in the numerator?

  6. anonymous
    • 5 years ago
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    yes

  7. anonymous
    • 5 years ago
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    then it goes to infinity

  8. anonymous
    • 5 years ago
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    it's asking "e raised to what power is infinity"

  9. anonymous
    • 5 years ago
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    but its infinity plus a number

  10. anonymous
    • 5 years ago
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    which is still infinity

  11. anonymous
    • 5 years ago
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    infinity added to, multiplied by, or divided by any constant is still infinity

  12. anonymous
    • 5 years ago
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    what if its is being added to zero

  13. anonymous
    • 5 years ago
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    still infinity But, if it is multiplied by zero it's undefined

  14. anonymous
    • 5 years ago
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    infinity is an odd thing

  15. anonymous
    • 5 years ago
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    oh ok thank you

  16. anonymous
    • 5 years ago
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    :)

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spraguer (Moderator)
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