anonymous
  • anonymous
what is the answer to this problem when you plug in infinity for t 1/5ln(5t+2)?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
0
anonymous
  • anonymous
why isnt it infinity
anonymous
  • anonymous
because any number divided by something approaching infinity goes to 0

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anonymous
  • anonymous
i wrote my question wrong
anonymous
  • anonymous
is ln(5t+2) in the numerator?
anonymous
  • anonymous
yes
anonymous
  • anonymous
then it goes to infinity
anonymous
  • anonymous
it's asking "e raised to what power is infinity"
anonymous
  • anonymous
but its infinity plus a number
anonymous
  • anonymous
which is still infinity
anonymous
  • anonymous
infinity added to, multiplied by, or divided by any constant is still infinity
anonymous
  • anonymous
what if its is being added to zero
anonymous
  • anonymous
still infinity But, if it is multiplied by zero it's undefined
anonymous
  • anonymous
infinity is an odd thing
anonymous
  • anonymous
oh ok thank you
anonymous
  • anonymous
:)

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