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what is the answer to this problem when you plug in infinity for t 1/5ln(5t+2)?

Mathematics
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0
why isnt it infinity
because any number divided by something approaching infinity goes to 0

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Other answers:

i wrote my question wrong
is ln(5t+2) in the numerator?
yes
then it goes to infinity
it's asking "e raised to what power is infinity"
but its infinity plus a number
which is still infinity
infinity added to, multiplied by, or divided by any constant is still infinity
what if its is being added to zero
still infinity But, if it is multiplied by zero it's undefined
infinity is an odd thing
oh ok thank you
:)

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