Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Help....too much math today. Show that the collection of all ordered 3-tuples (x1, x2, x3) whose components satisfy 3x1-x2+5x3=0 forms a vector space with respect to the usual operations of R3...don't really need an answer as much as I need someone to shed light on the problem :)

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

I think you may need to go through and show that it satisfies each axiom for being a vector space in Rn
closed under addition, closed under scalar multiplication, commutative addition, that a zero vector exists, etc
we are oinly given one vector though, where the axioms talk about having 2 vectors and adding them and such

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

you can make 2 arbitrary vectors and
oh ok thanks
then proceed through it. i.e. if both satisfy the equation, then 3(a+e) - (b+d) + 5(c + f) = 0
and do that sort of process with all the axioms
ok cool, I get it now

Not the answer you are looking for?

Search for more explanations.

Ask your own question