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anonymous

  • 5 years ago

Help....too much math today. Show that the collection of all ordered 3-tuples (x1, x2, x3) whose components satisfy 3x1-x2+5x3=0 forms a vector space with respect to the usual operations of R3...don't really need an answer as much as I need someone to shed light on the problem :)

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  1. anonymous
    • 5 years ago
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    I think you may need to go through and show that it satisfies each axiom for being a vector space in Rn

  2. anonymous
    • 5 years ago
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    closed under addition, closed under scalar multiplication, commutative addition, that a zero vector exists, etc

  3. anonymous
    • 5 years ago
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    we are oinly given one vector though, where the axioms talk about having 2 vectors and adding them and such

  4. anonymous
    • 5 years ago
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    you can make 2 arbitrary vectors <a, b, c> and <e, d, f>

  5. anonymous
    • 5 years ago
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    oh ok thanks

  6. anonymous
    • 5 years ago
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    then proceed through it. i.e. if both satisfy the equation, then 3(a+e) - (b+d) + 5(c + f) = 0

  7. anonymous
    • 5 years ago
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    and do that sort of process with all the axioms

  8. anonymous
    • 5 years ago
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    ok cool, I get it now

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