anonymous
  • anonymous
P(6 and 7)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Help Please have to go to sleep in alittle :(
anonymous
  • anonymous
can you give me more details
anonymous
  • anonymous
you roll one number cube twice. Find each Probability

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anonymous
  • anonymous
if its a 6 sided dice the probability is 0, because here is not a 7
anonymous
  • anonymous
so how would i right this P(6)=1/6 P(7)=0/6 P(6)*P(7)=0/6?
anonymous
  • anonymous
is this rigtht?
anonymous
  • anonymous
perhaps it's that you roll two dice, so you can numbers 2-12
anonymous
  • anonymous
o.o
anonymous
  • anonymous
is that possible?
anonymous
  • anonymous
So i got all of them Wrong Since i did /6
anonymous
  • anonymous
it says You Roll one Number cube TWICE. Find each probability
anonymous
  • anonymous
well to get 6, you could have (1 & 5)x2, (2&4)x2, 3&3
anonymous
  • anonymous
so it is talking about the sum, there is 5 ways to get a sum of 6, and 6 ways to get a sum of 7, so the probability would be 11/36
anonymous
  • anonymous
So ur saying i got everything wrong.
anonymous
  • anonymous
hmm, it's been a while since I've done probability, let me think for a second
anonymous
  • anonymous
So What do i do for P(6) and P(7)
anonymous
  • anonymous
there are 6 ways to roll one die...the ones that are relevant to us are 1 to 5 for the first die, so 5/6
anonymous
  • anonymous
then..
anonymous
  • anonymous
the p(6) is 5/36 since there is 5 ways to get a 6 (1 + 5, 5+1, 2+4, 4+2, 3+3) and there are 36 outcomes on 2 die
anonymous
  • anonymous
there is only one number on the next die that will give us our 6, no matter what we rolled first, so 1/6 for second
anonymous
  • anonymous
so the answer is 5/36?
anonymous
  • anonymous
I believe so...wish someone would jump in here
anonymous
  • anonymous
so for the 7, all 6 on the first die can give us 7...and only one on the next die so, 6/36 for 7
anonymous
  • anonymous
does that work for your question?

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