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anonymous

  • 5 years ago

Factor completely or state prime. 3x^3-36x^2+33x

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  1. anonymous
    • 5 years ago
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    divide all of these terms by x. what do you get?

  2. anonymous
    • 5 years ago
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    3x^2-36x+33?

  3. anonymous
    • 5 years ago
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    okay, and what do all of them have in common?

  4. anonymous
    • 5 years ago
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    / by 3

  5. anonymous
    • 5 years ago
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    okay so now you get x^2-12x+11. however the three and the x dont just poof away, so now you have: 3x(x^2-12x+11)

  6. anonymous
    • 5 years ago
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    3(x^2-12x+11)?

  7. anonymous
    • 5 years ago
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    close, remeber the 3 we also divided? so its: 3x(x^2-12x+11)

  8. anonymous
    • 5 years ago
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    but you can set the 3x aside for now, and just work with the x^2-12x+11

  9. anonymous
    • 5 years ago
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    wouldnt that make it 3x(x-12+11) wouldnt the x's be took out then?

  10. anonymous
    • 5 years ago
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    okay, your getting confued. we took the 3x out of this equation :3x^3-36x^2+33x

  11. anonymous
    • 5 years ago
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    so that would make it 3x(x^2-12x+11)

  12. anonymous
    • 5 years ago
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    ok

  13. anonymous
    • 5 years ago
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    are you ok now?

  14. anonymous
    • 5 years ago
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    I hope so I am mostly tryin to make sure I am getting these right for class. Help with ones like this one is a bonus. Thank You so much.

  15. anonymous
    • 5 years ago
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    no problem, just ask. ok, so were NOT finished yet, lol

  16. anonymous
    • 5 years ago
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    Nope lol

  17. anonymous
    • 5 years ago
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    x^2-12x+11 what are multiples of 11?

  18. anonymous
    • 5 years ago
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    1 and 11, right?

  19. anonymous
    • 5 years ago
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    (x-1)(x-11)

  20. anonymous
    • 5 years ago
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    then you multiply that out to see if you get x^2-12x+11. (x-1)(x-11) x^2-11x-x+11 x^2-12x+11' so it's right. now you finally add the 3x back final answer: 3x(x-1)(x-11)

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