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anonymous
 5 years ago
Factor completely or state prime. 3x^336x^2+33x
anonymous
 5 years ago
Factor completely or state prime. 3x^336x^2+33x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0divide all of these terms by x. what do you get?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, and what do all of them have in common?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so now you get x^212x+11. however the three and the x dont just poof away, so now you have: 3x(x^212x+11)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0close, remeber the 3 we also divided? so its: 3x(x^212x+11)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but you can set the 3x aside for now, and just work with the x^212x+11

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wouldnt that make it 3x(x12+11) wouldnt the x's be took out then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, your getting confued. we took the 3x out of this equation :3x^336x^2+33x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so that would make it 3x(x^212x+11)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I hope so I am mostly tryin to make sure I am getting these right for class. Help with ones like this one is a bonus. Thank You so much.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem, just ask. ok, so were NOT finished yet, lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^212x+11 what are multiples of 11?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you multiply that out to see if you get x^212x+11. (x1)(x11) x^211xx+11 x^212x+11' so it's right. now you finally add the 3x back final answer: 3x(x1)(x11)
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