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anonymous
 5 years ago
6(2z+5)<19z+16
anonymous
 5 years ago
6(2z+5)<19z+16

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Distribute the 6 into the paretheses 12z + 5 < 19z + 16 Next we want to put all terms with a z on one side and all constants on the other. I'll add 19z to both sides first. 7z + 5 < 16 Then I'll subtract 5 from both sides 7z < 11 Finally, divide both sides by 7 z < 11/7
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