anonymous
  • anonymous
6(-2z+5)<-19z+16
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Distribute the 6 into the paretheses -12z + 5 < -19z + 16 Next we want to put all terms with a z on one side and all constants on the other. I'll add 19z to both sides first. 7z + 5 < 16 Then I'll subtract 5 from both sides 7z < 11 Finally, divide both sides by 7 z < 11/7

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