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A box contains the letters M I S S I S S I P P I. What is the probability of selecting an S first and a P second, if: a. the first letter is not replaced? b. the first letter is replaced.

Mathematics
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4/11*2/10
because there are 4 S out of 11 letters, there is 2 P out of the remaining 10 letters
so the a. the first letter is not replaced what do i put?

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Other answers:

thus the number in the denominator goes from 11, the original number o letters in the word to 10, the remaining letters you can choose from
so what do i write????>?>
4/11*2/10=8/110 which reduces to 4/55
so that with the first letter not being replaced?
yes, you leave the S out when you get ready to draw the 2nd time
so the 2nd time on b. is the first letter is replaced what do i right
then you take 4/11*2/11 since there is 11 letters on each draw
so whats the answer?
if the 1st letter is replaced the answer is 4/11*2/11 = 8/121
Lols i really don't get this but ok can u explain clearly more about how u got all those Numbers

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