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anonymous

  • 5 years ago

how do i find the derivative of this using the chain rule please help somebody\[F(x)=x \sqrt{x ^{2}+1}\]

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  1. bahrom7893
    • 5 years ago
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    Okay first throw the x into the sqrt.

  2. bahrom7893
    • 5 years ago
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    F(x) = sqrt(x^4 + x^2)

  3. bahrom7893
    • 5 years ago
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    Or F(x) = (x^4+x^2)^(1/2)

  4. bahrom7893
    • 5 years ago
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    Now take the derivative: F'(x) = (1/2) * (x^4 + x^2 )^(-1/2) * (4x^3 + 2x)

  5. bahrom7893
    • 5 years ago
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    \[f'(x) = (4x^3+2x)/(2\sqrt(x^4+x^2))\]

  6. anonymous
    • 5 years ago
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    can u please explain the part when u threw the x into the square root

  7. bahrom7893
    • 5 years ago
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    okay x is the same as \[\sqrt{x^2}\]

  8. anonymous
    • 5 years ago
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    yep

  9. bahrom7893
    • 5 years ago
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    so to put it inside the sqrt, multiply everything inside by x^2

  10. anonymous
    • 5 years ago
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    ok great thank u soo much appreciate the help :)

  11. bahrom7893
    • 5 years ago
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    Can you click on Become a fan next to my name, please! Thanks =)

  12. anonymous
    • 5 years ago
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    sure

  13. anonymous
    • 5 years ago
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    can i ask u another question lol ?

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spraguer (Moderator)
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