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really having an issue with differentiables containing square roots and e^x

the derivative of e^x is always e^x, forever, it's its own derivative

what if a number is attached like the 9-e^x?

derivativave of 9 is 0,

ahh so you do seperate it... the derivative of 9 then e^x

right

\[(x(e ^{x}))-(1(9+e^{x}))/(9+e^{x})^{2}\]

Is that a different problem?

its not subtract its divide

x divided by 9+e^{x}

Ah, got it.

So:
\[f(x) = \frac{x}{9 + e^x}\]?

yes and the other was the answer i got

and thats the answer to fprime?

what is wrong with the answer i found?

Sorry, browser retardedness.

i feel ya

Also, what I meant was that you're looking at :
\[f(x) = x(9 + e^x)^{-1}\]

Looks like the only issue you had was a sign issue.

I ultimately got:
\[\frac{9 + e^x - xe^x}{(9 + e^x)^2}\]