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anonymous
 5 years ago
integral x/(x2)dx
i know u=x2, making du=dx
i tried rewriting as u+2/u but got nowhere.
anonymous
 5 years ago
integral x/(x2)dx i know u=x2, making du=dx i tried rewriting as u+2/u but got nowhere.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hmm, would this work? \[f(x) = x*u^{1}\]

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0u can't do that Moss's brother..andrew u were tryin the right approach, i think u made a mistake somewhere: (u+2)/u = u/u + 2/u = 1 + 2/u Now if u integrate that, u + 2Lnu, plug in u=x2 x2+2 Lnx2 <= Your answer..

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0Or x  2 +Ln(x2)^2+C (no need for absolute value as ^2 is always positive, and I forgot the C earlier) Please click on become a fan if I helped! Thanks!
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