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anonymous
 5 years ago
Take 4a  3b + 2c from 2a  3b + 4c.
a)2a + 2c
b)2a  2c
c)2a + 2c
d)2a  2c
anonymous
 5 years ago
Take 4a  3b + 2c from 2a  3b + 4c. a)2a + 2c b)2a  2c c)2a + 2c d)2a  2c

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't think any of your answers are correct....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just to clarify, do you mean (213b+4c)  (4a3b+2c)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0* in the first parentheses, I meant to write 2a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You add/subtract like terms, or the terms that are similar. I think you worded this problem sort of strangely because doing: (2a  3b + 4c)  (4a  3b + 2c) = 2a + 6, which isn't a solution given. Doing (4a  eb + 2c)  (2a  3b + 4c) = 2a2c. You set the two equations up on top of each other and subtract each term separately. 4a  3b + 2c Step 1: 4a  2b = 2a. 2a  3b + 4c Step 2: 3b  (3b) = 3b + 3b = 0  Step 3: 2c4c = 2c 2a + 0  2c 2a2c Does that make sense?
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