## anonymous 5 years ago In an exercise I found this $\int\limits \sqrt{a^2-x^2}dx=x \sqrt{a^2-x^2}-\int\limits \frac{x}{\sqrt{a^2-x^2}}dx$ what are the steps? Thanks!

1. bahrom7893

Use trig substitution method!!

2. anonymous

x=sin(t)?

3. bahrom7893

x = a Sin(t)

4. bahrom7893

dx = a cos(t) dt

5. anonymous

I got this but seems different why? $1/2a^2\arcsin(x)+1/2a^2\sin(2\arcsin(x))$

6. bahrom7893

i had a link to one site with all these... feelin too sick of math right now, lemme find the link, brb

7. bahrom7893

wait i just realized there supposed to be an arcsin there..

8. bahrom7893