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anonymous
 5 years ago
so iv just started the prime number challenge, please help, basically, im having trouble giving python a command, her is a simple version of the line
while x%y == >0:
this gives me syntax error, im trying to say that, if x/y leaves a remainder, then x=x1, if not, a+1 and repeat where a is the number being tested.... if that makes any sense? lol
anonymous
 5 years ago
so iv just started the prime number challenge, please help, basically, im having trouble giving python a command, her is a simple version of the line while x%y == >0: this gives me syntax error, im trying to say that, if x/y leaves a remainder, then x=x1, if not, a+1 and repeat where a is the number being tested.... if that makes any sense? lol

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hi if you want know the simplest way to solve the prime number .. here is the way. you dont need to check the whole number ,,,just start the for loop from two till you arrive to the half of the number that you are attempting to know if it is prime or not. here is the example of what i say ... for(int i=2;x/2;i++) if(x%i==0) it is not prime ; else it is prime.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you just need if x % y > 0 not ==

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0pmpn8ez is right, but didn't explain what is wrong with your statement. == and > are both comparison operations, so you're getting an error. Section 5.3 of the Python documentation can expand on this if you're interested. http://docs.python.org/library/stdtypes.html Hope this helps!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey, thanks to you both, i sorted it and you were both a big help, if you wouldn't mind taking a look at my new thread about 1b? would reallt be of help, thanks
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