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A prize wheen with a equal sectors numbered from 0 to 36 is spun 400 times. A prime number is the outcome 125 times. a) what is the theoreticcal probability of spinning a prime number? b) In 400 spins, how many times would you expect a prime number to occur ? c) compare your answer to part a) and part b) 4:59 pm

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ok so first question is, how many numbers are prime in 0 through 36?
i dont even know
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

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Other answers:

1,2,3,5,7,11,13,17,1..aww u bet me to it lol
haha it's all good :p, took me a while
1 is not prime
is it will be 11/ 36?
so if there are 11 prime numbers between 0 and 36, what is the probability of a single spin landing on a prime number?
probability = (possibilities of a prime)/(total number of possibiliies)
close! one problem is 0-36 is actually 37 numbers, since zero counts too :p
so 11/37 is the answer to a
so how do you think you get the answer to b?
oo waittt
in 400 spins
i dont kno
well, if I told you to flip a coin twice, how many times would you expect it lands heads, and how many times tails?
1 head or 1 tails .. lol
exactly - and the same principle applies here
so the probability of a coin landing heads is 1/2, since there are two sides, and heads is only one of them
so if you flipped it twice, you'd expect 1/2 * 2 heads to show up
so 1 head, and 1 tail
so now if the probability of spinning a prime is 11/37, how many primes would you expect to spin if you spun 400 times?
it's the same thing "probability of it happening once" x "number of attempts"
so 11/37 * 400
okay i get it
so you would expect 118.92 primes
you forgot a zero on the top
11/37 x 400 = (400*11)/37 = 118.92
so you would expect to spin 119 or so prime numbers
that's less than the 125 that were spun in the problem example - but within reason
so part (c) is - that person spun more primes than you'd expect, but not unreasonably so
how did you even get 118.92?
just chipping in if yo don't mind... my msn got messed up. fixed now :)
go for it =)
ok i get it :)
though i can't answer this question now, looks like its already solved but i'll try it on my own :)
A card is chosen from a deck of cards, recorded, and then replaced. this is done 75 times and red card from 5 to 9 is chosen 21 times. a) what is the theoretical probability of a red card between 5 and 9 being chosen? b) how many times would you expect this event to happen in 75 trials? c) compare your answers to part a) and b)

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