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ok so first question is, how many numbers are prime in 0 through 36?

i dont even know

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

1,2,3,5,7,11,13,17,1..aww u bet me to it lol

haha it's all good :p, took me a while

1 is not prime

is it will be 11/ 36?

probability = (possibilities of a prime)/(total number of possibiliies)

11/36?

close! one problem is 0-36 is actually 37 numbers, since zero counts too :p

so 11/37 is the answer to a

so how do you think you get the answer to b?

oo waittt

well

in 400 spins

i dont kno

1 head or 1 tails .. lol

exactly - and the same principle applies here

so if you flipped it twice, you'd expect 1/2 * 2 heads to show up

so 1 head, and 1 tail

it's the same thing "probability of it happening once" x "number of attempts"

so 11/37 * 400

okay
i get it

so you would expect 118.92 primes

484/37

you forgot a zero on the top

11/37 x 400 = (400*11)/37 = 118.92

so you would expect to spin 119 or so prime numbers

that's less than the 125 that were spun in the problem example - but within reason

so part (c) is - that person spun more primes than you'd expect, but not unreasonably so

how did you even get 118.92?

just chipping in if yo don't mind... my msn got messed up. fixed now :)

go for it =)

ok i get it :)

though i can't answer this question now, looks like its already solved but i'll try it on my own :)