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anonymous
 5 years ago
A card is chosen from a deck of cards, recorded, and then replaced. this is done 75 times and red card from 5 to 9 is chosen 21 times. a) what is the theoretical probability of a red card between 5 and 9 being chosen? b) how many times would you expect this event to happen in 75 trials? c) compare your answers to part a) and b)
anonymous
 5 years ago
A card is chosen from a deck of cards, recorded, and then replaced. this is done 75 times and red card from 5 to 9 is chosen 21 times. a) what is the theoretical probability of a red card between 5 and 9 being chosen? b) how many times would you expect this event to happen in 75 trials? c) compare your answers to part a) and b)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so this is similar to the last one. you want to know how many possibilities there are that a given event happens (in this case red 59), and how many possibilities there are total. The first things you need to determine are: 1. how many red cards are there between 5 and 9? 2. how many total cards are in the deck?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well how many red cards are there in a deck .. is it 26 >?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right, so there are 5,6,7,8,9 of diamonds and hearts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 10 total that are red AND 59

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are 52 cards in the deck total

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the probability of a red card that is 59 = 10 (the number of red 59)/52 (total number of cards)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, in a deck of cards, the red cards are diamonds and hearts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so there are two sets of 59 that are red  hearts and diamonds

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so in total, there are 5,6,7,8,9 of hearts, and 5,6,7,8,9 of diamonds, so 10 total

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the probability = (possible red 59) divided by ( total possible cards)

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0man i hate card problems.. how the heck would i know how many cards are there...I mean gambling is illegal in schols..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0true  so (a) = 10/52

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how do you think you get b?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do i rememeber all those red cards and everything?? coz itss hard :"S

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, the good news is that a deck of cards is used across a LOT of probability questions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it lik 10/52 * 75 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you just gotta know  there are 52 cards, 4 suits, 2 suits of each color, 13 cards in each suit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and yes, you are correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it happens :p and it will happen more the more you practice

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0and i still dont get it.. maybe im not tryin hard enough =/

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0embarassin really, bein good in calc and when someone asks me a stat question i gtg.. sorry i dunno..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha, well if you asked me a calc question I'd give you a blank stare :p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got aniother questin too

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k, I'd say ask a different one on the left side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and I'm sure many of us will make the jump

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok make sure that uhelp me lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ur supposed to be asking another question

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0shes tryin to do it on her own
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