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anonymous
 5 years ago
(x2)is greater than 2(2x1)(x1)... please show work
anonymous
 5 years ago
(x2)is greater than 2(2x1)(x1)... please show work

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The argument of a logarithm function must always be positive, so we have the restrictions x > 0 2x  1 > 0, equivalent to x > 1/2 x  2 > 0, equivalent to x > 2. This is the most restrictive condition, so it governs. Taking the antilog of both sides of the equation, we have x = (2x1)/(x2) x(x2) = 2x1 (multiply both sides by x2) x^2  2x = 2x  1 (use the distributive property to eliminate parentheses) x^2  4x + 1 = 0 (subtract 2x1 from both sides to put the equation into standard form) x = ((4) ±√((4)^2  4(1)(1)))/(2(1)) (apply the quadratic formula) x = (4 ±√(164))/2 (simplify) x = (4 ±2√3)/2 (simplify) x = 2±√3 (simplify) Since we know that x must be greater than 2, only the positive sign will give a suitable solution. x = 2+√3 ≈ 3.732 Check Ln[3.732] = Ln[2*3.7321]  Ln[3.732  2] 1.317 = Ln[7.464  1]  Ln[1.732] 1.317 = Ln[6.464]  .549 1.317 = 1.866  .549 (yes)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that what you r looking for

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in the back of the book it says that x>1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i mean that x is less than 1. it got the answer though thanks for the help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x+1)(x+2) is greater than (x+1)??????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x2) > 2(2x1)(x1) x2 > 4x^2  6x +2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use the AC method to factor.
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