anonymous
  • anonymous
find the derivative of the function at the given number f(x)=1-3x^2 at 2 i am confused i get -6xhsquared-6xh-h^2 all over h, plz help me
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
bahrom7893
  • bahrom7893
f'(x) = -6x f'(2) = -18
bahrom7893
  • bahrom7893
-12
bahrom7893
  • bahrom7893
-18 was a typo.. PLEASE CLICK ON BECOME A FAN IF I HELPED! PLEASE!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

bahrom7893
  • bahrom7893
btw where r u gettin h from?? Or was ur equation: (1-3x)^2 ?
bahrom7893
  • bahrom7893
can u post it properly?
anonymous
  • anonymous
1-3xsquared
anonymous
  • anonymous
h is in derivative formula?
anonymous
  • anonymous
are you using [f(x + h) - f(x)]/h
bahrom7893
  • bahrom7893
but why?? u will use diff rules for different problems, this one is just f' = -6x
anonymous
  • anonymous
if you know the short cut, but if you don't you use the formula
bahrom7893
  • bahrom7893
oh is he doin the limit definition?
anonymous
  • anonymous
i think so

Looking for something else?

Not the answer you are looking for? Search for more explanations.