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anonymous

  • 5 years ago

5^(X+2)=7^(X-3)

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  1. bahrom7893
    • 5 years ago
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    okay so take Natural log of both sides: Ln[5^(X+2)] = Ln[7^(X-3)]

  2. bahrom7893
    • 5 years ago
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    Now remember this rule: LnA^b = b*LnA, so apply it here: (x+2)*Ln5 = (x-3)*Ln7

  3. bahrom7893
    • 5 years ago
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    Multiply them out: xLn5 + 2Ln5 = xLn7 - 3Ln7

  4. bahrom7893
    • 5 years ago
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    move terms with x to one side and the ones without to the other side: xLn5-xLn7 = -3Ln7-2Ln5 Take x out from the left: x(Ln5-Ln7) = -3Ln7 - 2Ln5

  5. bahrom7893
    • 5 years ago
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    x = (-3Ln7 - 2Ln5)/(Ln5-Ln7)

  6. anonymous
    • 5 years ago
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    thanks so much

  7. bahrom7893
    • 5 years ago
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    Please click on become a fan if I helped! I want to get to 100, thanks you! =)

  8. anonymous
    • 5 years ago
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    where do you go to become a fan?

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