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anonymous
 5 years ago
25^(2x)=5^(x^212)
anonymous
 5 years ago
25^(2x)=5^(x^212)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Change it into this equation (5^2)^(2x)=5^(x^212)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0therefore x=6 or x=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.025 = 5^2 left side (5^2)^(2x) then multiply exponents and get 5^4x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if 5^4x = 5^(x^212) since the bases are the same you just have 4x = x^2  12, now factor or use the quadratic formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.025^(2x)=5^(x^212) 5^4x = 5^(x^212) we have the same base 5 therefore \[4x=x^212\] \[0=x^24x12\] \[0=(x6)(x+2)\] x6=0 x=6 x+2=0 x=2
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