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find the area of the region that is bounded by these equations,, 1) y=lnx, x-axis, x= e^2 2) y = x^2, y = 8-x^, 4x - y +12 =0

Mathematics
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have you done integration yet?
not yer
is calculus class?

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Other answers:

yes
Then I think only way to solve it is by using integration. Are you familiar with the concept of integration
yes
So graph two function in calculator. Which one is on top?
you know how ln(x) curve look like. Also x=e^2 is verticle line.
ln(x) is 0 when x=1 right? so you will \[\int\limits_{1}^{e^2}\ln(x) dx\]
did you get it?
wait
the answer here in the handout is \[e ^2 +1\]
Yes http://www.wolframalpha.com/input/?i=integral+1+to+e^2%28ln%28x%29+
i got it now... :)
but how can i draw y=lnx and x= e^2 in the cartesian plane
e^2 verticle line
how can i solve for its x and y coordinate?

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