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have you done integration yet?

not yer

is calculus class?

yes

yes

So graph two function in calculator. Which one is on top?

you know how ln(x) curve look like. Also x=e^2 is verticle line.

ln(x) is 0 when x=1 right?
so you will \[\int\limits_{1}^{e^2}\ln(x) dx\]

did you get it?

wait

the answer here in the handout is \[e ^2 +1\]

Yes
http://www.wolframalpha.com/input/?i=integral+1+to+e^2%28ln%28x%29+

i got it now... :)

but how can i draw y=lnx and x= e^2 in the cartesian plane

e^2 verticle line

how can i solve for its x and y coordinate?