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anonymous

  • 5 years ago

find the area of the region that is bounded by these equations,, 1) y=lnx, x-axis, x= e^2 2) y = x^2, y = 8-x^, 4x - y +12 =0

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  1. anonymous
    • 5 years ago
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    have you done integration yet?

  2. anonymous
    • 5 years ago
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    not yer

  3. anonymous
    • 5 years ago
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    is calculus class?

  4. anonymous
    • 5 years ago
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    yes

  5. anonymous
    • 5 years ago
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    Then I think only way to solve it is by using integration. Are you familiar with the concept of integration

  6. anonymous
    • 5 years ago
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    yes

  7. anonymous
    • 5 years ago
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    So graph two function in calculator. Which one is on top?

  8. anonymous
    • 5 years ago
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    you know how ln(x) curve look like. Also x=e^2 is verticle line.

  9. anonymous
    • 5 years ago
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    ln(x) is 0 when x=1 right? so you will \[\int\limits_{1}^{e^2}\ln(x) dx\]

  10. anonymous
    • 5 years ago
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    did you get it?

  11. anonymous
    • 5 years ago
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    wait

  12. anonymous
    • 5 years ago
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    the answer here in the handout is \[e ^2 +1\]

  13. anonymous
    • 5 years ago
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    Yes http://www.wolframalpha.com/input/?i=integral+1+to+e^2%28ln%28x%29+

  14. anonymous
    • 5 years ago
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    i got it now... :)

  15. anonymous
    • 5 years ago
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    but how can i draw y=lnx and x= e^2 in the cartesian plane

  16. anonymous
    • 5 years ago
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    e^2 verticle line

  17. anonymous
    • 5 years ago
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    how can i solve for its x and y coordinate?

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