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anonymous
 5 years ago
the maximum value of function
y=x^2+2x+1
anonymous
 5 years ago
the maximum value of function y=x^2+2x+1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, first differentiate with respect to x: dy/dx=2x+2. Set equal to zero and solve for x, x=1. Now check second derivative. d^2y/dx^2=2, Since the second derivative is greater than zero for all x, x = 1 has to correspond to a maximum. Now, plug in x = 1 into the original equation to obtain: (1,0)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops thats wrong srry
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