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anonymous
 5 years ago
Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of N 51o W at 14 miles per hour, and the other travels at a bearing of S 56o W at 17 miles per hour. Approximate the distance between them at noon the same day. Round answer to two decimal places.
anonymous
 5 years ago
Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of N 51o W at 14 miles per hour, and the other travels at a bearing of S 56o W at 17 miles per hour. Approximate the distance between them at noon the same day. Round answer to two decimal places.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it 51 degree north of west

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A. 20.33 miles B. 43.25 miles C. 28.20 miles D. 22.72 miles E. 37.19 miles

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that doesnt seem reasonable......because it said round your answer to two decimal points. oh answers!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find x and Y component of speed of each ship

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so ship a would be 28 miles and shib b would be 34 miles i think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here How I would solve it .. Ship 1 travel at 51 degree North of West Using standard coordinate system X component of speed is cos(51)*14 Y component of speed is sin(51)*14

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you will get speed of two ship

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Multiply x and Y component of each ship seperately to find position then just use distance formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so ship a is 97.49 ship b is 128.6 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0X position of Ship 1 at noon(1210am) cos(51)*14 mile per hours * 2hour 17.62 Y position of Ship 2 at noon sin(51)*14*2=21.76

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0X position of Ship 2 cos(56)*17*2=something Y position of Ship 2 sin(56)*17*2=something Distance Formula \[\sqrt(ship 1 (x) position  ship 2( x) position)^2+ship 1 (y) position  ship 2( y) position)^2)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0X position of Ship 2 cos(56)*17*2=23.89 Y position of Ship 2 sin(56)*17*2=17.73

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then I just plug those into the formula?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got 19.01 for x position of ship 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmmm ok you're probably right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you see the distance formula in full

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is basically square root of (xposition of ship 1 xpos ship 2)^2 + (ypos ship 1y pos ship 2)^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is it physics or math?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Were you able to get answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I have to go back to the begining and replug in stuff cause i messed something up hold on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I will do the same thing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I read that problem wrong it is 51 degree west of north  not north of west so I have to switch sin to cos vice versa

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay I have no clue what i did then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ship 1 position X:  sin(51)*14*2  A Y: cos(51)*14*2 B Ship 2 position X: sin(56)*17*2  C Y: cos(56)*17*2 D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt((AC)^2+(BD)^2)
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