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is it 51 degree north of west

A.
20.33 miles
B.
43.25 miles
C.
28.20 miles
D.
22.72 miles
E.
37.19 miles

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Find x and Y component of speed of each ship

ok so ship a would be 28 miles and shib b would be 34 miles i think

This is just ship 1

okay

try this with ship 2

so you will get speed of two ship

Multiply x and Y component of each ship seperately to find position
then just use distance formula

ok so
ship a is -97.49
ship b is 128.6
?

X position of Ship 2
-cos(56)*17*2=-23.89
Y position of Ship 2
-sin(56)*17*2=17.73

so then I just plug those into the formula?

I got 19.01 for x position of ship 2

hmmm ok you're probably right

Yep

can you see the distance formula in full

no

it is basically
square root of (xposition of ship 1- xpos ship 2)^2 + (ypos ship 1-y pos ship 2)^2)

Is it physics or math?

math trig/pre calc

Were you able to get answer

ok I have to go back to the begining and replug in stuff cause i messed something up hold on

I will do the same thing

ok thanks

I got 45.73.....?

The answer is 37.19

okay I have no clue what i did then

okay

sqrt((A-C)^2+(B-D)^2)

=37.19

ok thank you!

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