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the integral of 1/U^2 -16 is 1/*ln(u-4/u+4). i have determine whether it diverges or converges intergal 4 to zero 1/u^2-16

Mathematics
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over what interval?
4 to 0
is your integration right?

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Other answers:

the integration is wrong is it not
let me check
srry i meant to write 1/8(ln u-4/u+4)
yh tht's better
for simplcity I will write down as 1/8 ln(u-4) - ln(u+4)
okay great
1/8(ln(R-4)-ln(R+4) - 1/8(ln(-4)-(ln(4))
as R approach 4 the first term become -infinity
its because it becomes ln (0/0)
ln(0) approach infinity
negative infinity
why
http://www.wolframalpha.com/input/?i=ln%280%29
k
ty
still problem?

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