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anonymous

  • 5 years ago

the integral of 1/U^2 -16 is 1/*ln(u-4/u+4). i have determine whether it diverges or converges intergal 4 to zero 1/u^2-16

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  1. anonymous
    • 5 years ago
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    over what interval?

  2. anonymous
    • 5 years ago
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    4 to 0

  3. anonymous
    • 5 years ago
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    is your integration right?

  4. anonymous
    • 5 years ago
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    the integration is wrong is it not

  5. anonymous
    • 5 years ago
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    let me check

  6. anonymous
    • 5 years ago
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    srry i meant to write 1/8(ln u-4/u+4)

  7. anonymous
    • 5 years ago
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    yh tht's better

  8. anonymous
    • 5 years ago
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    for simplcity I will write down as 1/8 ln(u-4) - ln(u+4)

  9. anonymous
    • 5 years ago
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    okay great

  10. anonymous
    • 5 years ago
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    1/8(ln(R-4)-ln(R+4) - 1/8(ln(-4)-(ln(4))

  11. anonymous
    • 5 years ago
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    as R approach 4 the first term become -infinity

  12. anonymous
    • 5 years ago
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    its because it becomes ln (0/0)

  13. anonymous
    • 5 years ago
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    ln(0) approach infinity

  14. anonymous
    • 5 years ago
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    negative infinity

  15. anonymous
    • 5 years ago
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    why

  16. anonymous
    • 5 years ago
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    http://www.wolframalpha.com/input/?i=ln%280%29

  17. anonymous
    • 5 years ago
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    k

  18. anonymous
    • 5 years ago
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    ty

  19. anonymous
    • 5 years ago
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    still problem?

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