anonymous
  • anonymous
How do you solve 5x^2 = 2x +1 by completing the square?
Mathematics
schrodinger
  • schrodinger
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bahrom7893
  • bahrom7893
firs move everything to the left: 5x^2 - 2x -1 = 0
anonymous
  • anonymous
okay
bahrom7893
  • bahrom7893
divide everything by 5

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anonymous
  • anonymous
2x^2-5x-3 = 0 (2x + 1)(x - 3) = 0 x = -1/2 or x = 3
bahrom7893
  • bahrom7893
x^2 - (2/5)x - 1/5 = 0
bahrom7893
  • bahrom7893
So now u have the form of x^2 - 2ax +a^2, and ur a = 1/5
anonymous
  • anonymous
i already have the answer i just cant seem to get the answer
bahrom7893
  • bahrom7893
5x^2 - 2x - a^2 +a^2 - 1 = 0 5x^2 - 2x - 1/25 + 1/25 - 1 = 0
bahrom7893
  • bahrom7893
rewrite: sorry the 5s in front of x shouldnt be there
bahrom7893
  • bahrom7893
x^2 - 2x - a^2 +a^2 - 1 = 0 x^2 - 2x - 1/25 + 1/25 - 1 = 0 x^2 - 2x + 1/25 - 1/25 - 1 = 0
anonymous
  • anonymous
?????????
anonymous
  • anonymous
okay now what
anonymous
  • anonymous
i got some thing diff whow did you get that
bahrom7893
  • bahrom7893
what the heck, now i forgot the 5s, ughh sorry lets start over..
anonymous
  • anonymous
ahaa would it help if you had the answers
bahrom7893
  • bahrom7893
no, i know them, i just hate typin out math solutions
anonymous
  • anonymous
it says in the book that the answer is x+ 1/5 plus or minus the square root od 5/2
anonymous
  • anonymous
please :)
bahrom7893
  • bahrom7893
5x^2 - 2x -1 = 0 x^2 - (2/5)x + 1/5 = 0 x^2 - (2/5)x + 1/25 - 1/25 + 1/5 = 0
anonymous
  • anonymous
2x^2-5x-3 = 0 (2x + 1)(x - 3) = 0 x = -1/2 or x = 3
bahrom7893
  • bahrom7893
x^2 - 2 (1/5) x + (1/5)^2 - 1/25 + 1/5
anonymous
  • anonymous
that is what i got but i can be wrong
bahrom7893
  • bahrom7893
ur copying the wrong question dkglenn, stop confusing us
anonymous
  • anonymous
dkglenn ur wrong sorry
anonymous
  • anonymous
oh ok
bahrom7893
  • bahrom7893
so: x^2 - 2 (1/5) x + (1/5)^2 - 1/25 + 1/5 = 0
bahrom7893
  • bahrom7893
see u have to recognize that: x^2 - 2 (1/5) x + (1/5)^2 is the same as: (x - 1/5)^2
anonymous
  • anonymous
ok
bahrom7893
  • bahrom7893
(x - 1/5)^2 - 1/25 + 1/5 = 0 (x - 1/5)^2 = 1/25 - 1/5
bahrom7893
  • bahrom7893
wait smth went wrong lemme check my arithmetic
anonymous
  • anonymous
mkayy
anonymous
  • anonymous
ive done the problem 5 diff times..so stressed so thanks for trying
bahrom7893
  • bahrom7893
okay so let me post the problem over again, thread is too long
anonymous
  • anonymous
mkay

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