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anonymous

  • 5 years ago

How do you solve 5x^2 = 2x +1 by completing the square?

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  1. bahrom7893
    • 5 years ago
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    firs move everything to the left: 5x^2 - 2x -1 = 0

  2. anonymous
    • 5 years ago
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    okay

  3. bahrom7893
    • 5 years ago
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    divide everything by 5

  4. anonymous
    • 5 years ago
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    2x^2-5x-3 = 0 (2x + 1)(x - 3) = 0 x = -1/2 or x = 3

  5. bahrom7893
    • 5 years ago
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    x^2 - (2/5)x - 1/5 = 0

  6. bahrom7893
    • 5 years ago
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    So now u have the form of x^2 - 2ax +a^2, and ur a = 1/5

  7. anonymous
    • 5 years ago
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    i already have the answer i just cant seem to get the answer

  8. bahrom7893
    • 5 years ago
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    5x^2 - 2x - a^2 +a^2 - 1 = 0 5x^2 - 2x - 1/25 + 1/25 - 1 = 0

  9. bahrom7893
    • 5 years ago
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    rewrite: sorry the 5s in front of x shouldnt be there

  10. bahrom7893
    • 5 years ago
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    x^2 - 2x - a^2 +a^2 - 1 = 0 x^2 - 2x - 1/25 + 1/25 - 1 = 0 x^2 - 2x + 1/25 - 1/25 - 1 = 0

  11. anonymous
    • 5 years ago
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    ?????????

  12. anonymous
    • 5 years ago
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    okay now what

  13. anonymous
    • 5 years ago
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    i got some thing diff whow did you get that

  14. bahrom7893
    • 5 years ago
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    what the heck, now i forgot the 5s, ughh sorry lets start over..

  15. anonymous
    • 5 years ago
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    ahaa would it help if you had the answers

  16. bahrom7893
    • 5 years ago
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    no, i know them, i just hate typin out math solutions

  17. anonymous
    • 5 years ago
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    it says in the book that the answer is x+ 1/5 plus or minus the square root od 5/2

  18. anonymous
    • 5 years ago
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    please :)

  19. bahrom7893
    • 5 years ago
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    5x^2 - 2x -1 = 0 x^2 - (2/5)x + 1/5 = 0 x^2 - (2/5)x + 1/25 - 1/25 + 1/5 = 0

  20. anonymous
    • 5 years ago
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    2x^2-5x-3 = 0 (2x + 1)(x - 3) = 0 x = -1/2 or x = 3

  21. bahrom7893
    • 5 years ago
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    x^2 - 2 (1/5) x + (1/5)^2 - 1/25 + 1/5

  22. anonymous
    • 5 years ago
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    that is what i got but i can be wrong

  23. bahrom7893
    • 5 years ago
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    ur copying the wrong question dkglenn, stop confusing us

  24. anonymous
    • 5 years ago
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    dkglenn ur wrong sorry

  25. anonymous
    • 5 years ago
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    oh ok

  26. bahrom7893
    • 5 years ago
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    so: x^2 - 2 (1/5) x + (1/5)^2 - 1/25 + 1/5 = 0

  27. bahrom7893
    • 5 years ago
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    see u have to recognize that: x^2 - 2 (1/5) x + (1/5)^2 is the same as: (x - 1/5)^2

  28. anonymous
    • 5 years ago
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    ok

  29. bahrom7893
    • 5 years ago
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    (x - 1/5)^2 - 1/25 + 1/5 = 0 (x - 1/5)^2 = 1/25 - 1/5

  30. bahrom7893
    • 5 years ago
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    wait smth went wrong lemme check my arithmetic

  31. anonymous
    • 5 years ago
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    mkayy

  32. anonymous
    • 5 years ago
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    ive done the problem 5 diff times..so stressed so thanks for trying

  33. bahrom7893
    • 5 years ago
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    okay so let me post the problem over again, thread is too long

  34. anonymous
    • 5 years ago
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    mkay

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