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anonymous

  • 5 years ago

determine if diverge or coverge integral 3 to -3 y/sqrt 9-y^2

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  1. anonymous
    • 5 years ago
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    \[ \int\limits_{-3}^{3} y/9-y^2\]

  2. anonymous
    • 5 years ago
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    is this correct

  3. anonymous
    • 5 years ago
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    ?

  4. anonymous
    • 5 years ago
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    yah

  5. anonymous
    • 5 years ago
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    no srry

  6. anonymous
    • 5 years ago
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    there is a square root sih around the 9- y^2

  7. anonymous
    • 5 years ago
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    Okay let see

  8. bahrom7893
    • 5 years ago
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    0

  9. anonymous
    • 5 years ago
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    u=9-y^2 du=-2y dy

  10. bahrom7893
    • 5 years ago
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    lol i dunno the rest, i can solve the integral, i suck at series, sorry...=(

  11. anonymous
    • 5 years ago
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    \[\sqrt(u)du\]

  12. anonymous
    • 5 years ago
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    can i also use u substitution

  13. anonymous
    • 5 years ago
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    \[-2\int\limits(du/\sqrt(u)\]

  14. anonymous
    • 5 years ago
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    i mean trig subsitution

  15. anonymous
    • 5 years ago
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    yes that's what I did

  16. anonymous
    • 5 years ago
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    Trig is more work

  17. anonymous
    • 5 years ago
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    yah i had a hard time going that route

  18. anonymous
    • 5 years ago
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    just use u-sub don't use trig sub unless you really have to

  19. anonymous
    • 5 years ago
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    kk

  20. anonymous
    • 5 years ago
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    im kinda stuck on the last step when plug back the points

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