wolf
  • wolf
3x(y)^(1/3) can someone help me implicitly differentiate this?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
3[x*y^(1/3)] 3[x*(1/3)y'y^(-2/3) + y^(1/3)] y'[x/y^(2/3)] + 3y^(1/3)
wolf
  • wolf
heres the rest of the problem
wolf
  • wolf
+3y'=0

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wolf
  • wolf
whats the slope?
wolf
  • wolf
im just tryinging to make sure im doing this right
bahrom7893
  • bahrom7893
y' = x*y^(1/3), are u given x and y
wolf
  • wolf
-3y^(1/3)/(x/(y^(2/3))+3)?
wolf
  • wolf
2,8
wolf
  • wolf
i left out a +3y in the original equation because i can do that easy lol
bahrom7893
  • bahrom7893
wait a second can u post the whole equation? its not 3y'? its 3y?
wolf
  • wolf
3x(y)^(1/3)+3y
wolf
  • wolf
so the derivative is y'[x/y^(2/3)] + 3y^(1/3) + 3y'
bahrom7893
  • bahrom7893
k workin on it
wolf
  • wolf
or thats what that other dude said it was atleast haha
bahrom7893
  • bahrom7893
uploadin the solution
bahrom7893
  • bahrom7893
can u please click on become a fan?! LOL I wanna get to 100 the answer is -12/7 btw
bahrom7893
  • bahrom7893
http://i51.tinypic.com/2m68nyo.jpg

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