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wolf

  • 5 years ago

3x(y)^(1/3) can someone help me implicitly differentiate this?

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  1. anonymous
    • 5 years ago
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    3[x*y^(1/3)] 3[x*(1/3)y'y^(-2/3) + y^(1/3)] y'[x/y^(2/3)] + 3y^(1/3)

  2. Wolf
    • 5 years ago
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    heres the rest of the problem

  3. Wolf
    • 5 years ago
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    +3y'=0

  4. Wolf
    • 5 years ago
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    whats the slope?

  5. Wolf
    • 5 years ago
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    im just tryinging to make sure im doing this right

  6. bahrom7893
    • 5 years ago
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    y' = x*y^(1/3), are u given x and y

  7. Wolf
    • 5 years ago
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    -3y^(1/3)/(x/(y^(2/3))+3)?

  8. Wolf
    • 5 years ago
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    2,8

  9. Wolf
    • 5 years ago
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    i left out a +3y in the original equation because i can do that easy lol

  10. bahrom7893
    • 5 years ago
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    wait a second can u post the whole equation? its not 3y'? its 3y?

  11. Wolf
    • 5 years ago
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    3x(y)^(1/3)+3y

  12. Wolf
    • 5 years ago
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    so the derivative is y'[x/y^(2/3)] + 3y^(1/3) + 3y'

  13. bahrom7893
    • 5 years ago
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    k workin on it

  14. Wolf
    • 5 years ago
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    or thats what that other dude said it was atleast haha

  15. bahrom7893
    • 5 years ago
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    uploadin the solution

  16. bahrom7893
    • 5 years ago
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    can u please click on become a fan?! LOL I wanna get to 100 the answer is -12/7 btw

  17. bahrom7893
    • 5 years ago
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    http://i51.tinypic.com/2m68nyo.jpg

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