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anonymous

  • 5 years ago

how to calculate the natural domain of 1/x+9 ?

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  1. anonymous
    • 5 years ago
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    do you mean y = 1/(x+9) ?

  2. anonymous
    • 5 years ago
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    yeah

  3. anonymous
    • 5 years ago
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    sry about that

  4. anonymous
    • 5 years ago
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    no problem, so for a problem like this, you need to set the denominator (bottom part) of the fraction to 0, because that's where the function is undefined (you can't divide by zero). x+9=0, so x = -9, so the natural domain is all real numbers except -9. in math notation, this would be (-infinity, -9) U (-9, infinity). the parentheses mean that -9 is not included (brackets would mean that it is included, and the convention is that "we never quite reach infinity"). the U means "union", meaning that the domain is the combination of every value in either set of numbers. let me know if you have any questions.

  5. anonymous
    • 5 years ago
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    thank you so much!

  6. anonymous
    • 5 years ago
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    i got one more question, anyone there?

  7. anonymous
    • 5 years ago
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    hey, i'm still here. what's up?

  8. anonymous
    • 5 years ago
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    hey, its just a easy exercise on absolute value

  9. anonymous
    • 5 years ago
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    http://www.twiddla.com/499656 there's a whiteboard there, its easier for me to explain

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