anonymous
  • anonymous
can anyone help me understand this problem Solve using the addition principle. Graph and write set-builder notation and interval notation for each answer. 5(t + 3) + 9 ≥ 3(t − 2) − 10 i have solved it but not sure if i got it right {t|t ≥ 0} or (–∞, 0]
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
what class is it for. Algebra or set theory?
anonymous
  • anonymous
basic algebra
anonymous
  • anonymous
Can you tell me how you arrived at that solution?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
5(t + 3) + 9 ≥ 3(t − 2) − 10 5t+3+9 ≥ 3t-2-10 5t+12 ≥ 3t-12 5t-3t +12-12 ≥ 3t-3t-12+12 2t /2 ≥ 0/2 t≥0 that was the answer i got
anonymous
  • anonymous
I think I see what you did wrong
anonymous
  • anonymous
5(t+3)+9>or= 3(t-2)-10 You have to use distributive property.(Everything inside the parenthesis should be multiplied by number outside.)
anonymous
  • anonymous
dam it cant believe i let that one by me
anonymous
  • anonymous
So it is 5*t+5*3+9>0r=3*t+(3*-2) -10
anonymous
  • anonymous
So did you end up getting an answer?
anonymous
  • anonymous
working it out now
anonymous
  • anonymous
5(t + 3) + 9 ≥ 3(t − 2) − 10 5t+15+9 ≥ 3t-6-10 5t+24 ≥ 3t-16 5t-3t +24-24 ≥ 3t-3t-16+24 2t /2 ≥ 8/2 t≥4 {t|t ≥ 4} or (–∞, 4]
anonymous
  • anonymous
not sure about the last line though thats whats messing me up
anonymous
  • anonymous
since t is greater or equal to 4 we should start from 4 to infinity. so it should be [4,infinity)
anonymous
  • anonymous
ok so i have the answer backwards 5(t + 3) + 9 ≥ 3(t − 2) − 10 5t+15+9 ≥ 3t-6-10 5t+24 ≥ 3t-16 5t-3t +24-24 ≥ 3t-3t-16+24 2t /2 ≥ 8/2 t≥4 {t|t ≥ 4} or [4,∞)
anonymous
  • anonymous
thank you i see im going to hate my next math class more then this one

Looking for something else?

Not the answer you are looking for? Search for more explanations.